Shell_구구단(for문)

 

 

1

#!/bin/bash
  
   dan=5
   count=1
  
  
  
   for ((i=1 ; i<10 ; i++))
   do
      num=$(bc <<< "$dan*$i")
      echo "$dan * $i = $num"
 
  done

 

 

2

#!/bin/bash

dan=5
count=1

echo "$dan * $count = $((dan*$count))"

3

1 #!/bin/bash
  2
  3 for((dan=2; dan<10; dan++))
  4 do
  5     for ((count=1; count<10; count++))
  6     do
  7         echo "$dan * $count = $((dan*$count))"
  8     done
  9 done

#!/bin/bash

DAN=5
#expr
for ((COUNT=0; COUNT<10; COUNT++)) do
    echo "$DAN x $COUNT = "`expr $DAN \* $COUNT`
done

#bc 버전
for ((COUNT=0; COUNT<10; COUNT++)) do
     echo "$DAN x $COUNT = "`echo "$DAN*$COUNT"|bc`
done

#바로 계산하는 버전
for ((COUNT=0; COUNT<10; COUNT++)) do
    echo "$DAN * $COUNT = $(($DAN*$COUNT))"
done